G(-2)=2x^2+10

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Solution for G(-2)=2x^2+10 equation: 



(-2)=2G^2+10

We move all terms to the left:

(-2)-(2G^2+10)=0

We add all the numbers together, and all the variables

-(2G^2+10)-2=0

We get rid of parentheses

-2G^2-10-2=0

We add all the numbers together, and all the variables

-2G^2-12=0

a = -2; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·(-2)·(-12)
Δ = -96
Delta is less than zero, so there is no solution for the equation

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